How to find right part of custom XML to overwrite?

[shobull]

Hi,

I'm generating many word documents using repeating sections, but I need every document with different datas (different xml files). I've made docx template and bound XML file with testing data. Now I'd like to rewrite XML file with new one, but in customXml folder, there are item1.xml, item2.xml, item3.xml and item4.xml. How can I found out IN PROGRAM, which file should I rewrite? (Of course, I can find the right file unzipping and opening the files, but I want to find it in my program, because first time item1.xml was the file with data, but second time it was item3.xml).

Thanks for all answers!

[jason]

See https://github.com/plutext/OpenDoPE-WAR and in particular CustomXmlUtils.

The pattern is:

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Using java Syntax Highlighting

// Find custom xml item id
                String itemId = CustomXmlUtils.getCustomXmlItemId(wordMLPackage).toLowerCase();
                System.out.println("Looking for item id: " + itemId);

                // Inject data_file.xml        
                CustomXmlDataStoragePart customXmlDataStoragePart
                        = wordMLPackage.getCustomXmlDataStorageParts().get(itemId);
                if (customXmlDataStoragePart==null) {
                        throw new WebApplicationException(
                                        new Docx4JException("Couldn't find CustomXmlDataStoragePart"),
                                        Status.UNSUPPORTED_MEDIA_TYPE);
                }
                customXmlDataStoragePart.getData().setDocument(xis);
 

Parsed in 0.015 seconds, using GeSHi 1.0.8.4

[shobull]

Thanx Jason for your quick reply. It helped me a lot!